Michael J. answered 11/27/17
Tutor
5
(5)
Effective High School STEM Tutor & CUNY Math Peer Leader
1)
9x + 1 = (1/3)2x
Convert to common base.
(32)x - 1 = (3-1)2x
Equate exponents.
2(x - 1) = -2x
Solve for x.
2)
ln(x + 2) = 3
The solution to a natural log is the exponent of base number e.
e3 = x + 2
Solve for x.
3)
Move all log to one side of the equation, and non-log terms to the other side.
log27x + log27(x - 0.4) = 1
Condense the logs using the properties.
log27(x(x - 0.4)) = 1
log27(x2 - 0.4x) = 1
1 is the same as log27(27).
log27(x2 - 0.4x) = log27(27)
Equate the arguments of logs.
x2 - 0.4x = 27
Solve for x.
4)
logb6 = 1/2
b1/2 = 6
√b = 6
Solve for b.