Arturo O. answered 11/27/17
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From the definition of pH, you know that
[H3O+][OH-] = 10-14
So if you are given [H3O+] and you want to find [OH-],
[OH-] = 10-14 / [H3O+]
Similarly, if you are given [OH-] and you want to find [H3O+],
[H3O+] = 10-14 / [OH-]
I will do the first one for you. The others are solved similarly.
(a)
[OH-] = 2.07 × 10-7
[H3O+] = 10-14 / [OH-] = 10-14 / (2.07 × 10-7) = 4.83 x 10-8
Find pH to determine if acid or base.
pH = -log[H3O+] = -log(4.83 x 10-8) = 7.32 > 7 ⇒ base (if < 7, acid)
Do the others the same way.
James H.
Hello, I am having a small problem with what your math shows. It is not at your fault but my lack of understanding. How did you get from 10^-14/10^-14/2.07x10^-7 to 4.83x10-8? That isn't explained in enough detail and I have had no luck working through your math. The closest I got to the starting number of 2.07 through reverse engineering your math as shown was 2.3X10^-29.12/03/21