Calculate the concentration of unknown vinegar in the solution

Question

14 mL of 0.10 M NaOH was needed to neutralize 15 mL of vinegar solution of unknown concentration. Calculate the concentration of the unknown vinegar solution in gram per liter 

Answer 1

The balanced equation for the reaction is

NaOH + CH3COOH ==> H2O + CH3COONa

mmoles NaOH used = 14 ml x 0.10 mmol/ml = 1.4 mmoles

mmoles acetic acid present = 1.4 mmoles CH3COOH (1:1 mole ratio in balanced equation)

grams CH3COOH present = 1.4 mmoles x 60.05 mg/mmole = 84.07 mg

concentration in grams/liter:  84.07 mg/15 ml = 5.6 mg/ml = 5.6 g/liter