
Arturo O. answered 11/23/17
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Some of the numbers in the problem statement appear to be doubled, like 9090% and 33 hours. I assume you meant 90% and 3 hours.
P/A = power per m2 at 100% efficiency = 1000 W/m2 = 1000 J/(m2s)
η = efficiency in decimal form = 0.90
A = surface area of photovoltaic cells = 1 m2
t = seconds of direct sunlight each day = 3(3600) s = 10800 s
E = energy produced each day
E = η(P/A)At = 0.90 [1000 J/(m2s)] (1 m2) (10800 s) = 9,720,000 J = 9.72 MJ
Average power in watts:
<P> = η(P/A)A = 0.90 [1000 J/(m2s)] (1 m2) = 900 J/s = 900 Watts