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# An orginization collected \$30.25, there are two times as many dimes as nickles, how many are there of each?

coin word problem. collected \$30.25 in one day. two times as many dimes as nickles, how many OF EACH?

### 1 Answer by Expert Tutors

Pierce O. | Graduate Mathematics Student, Will Tutor Any Math SubjectGraduate Mathematics Student, Will Tutor...
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Hi Ashley,

To solve this question, we first come up with a formula representing the dollar amount given n nickels and d dimes. Nickels are worth \$0.05 each, and dimes \$0.10 each. No suprise here. So, the total dollar amount D, given n nickels and d dimes, can be expressed as:

D=0.05n + 0.10d

We have that the orginization collected \$30.25 in one day, so

30.25 = 0.05n + 0.10d

Also, we know that there are twice as many dimes as nickels, so

d = 2n

Now, if we substitute our expression for d into our total dollar amount equation, we have

30.25 = 0.05n + 0.10d

= 0.05n + 0.10(2n)

= 0.05n + 0.20n

= 0.25n

Solving for n, we find that

n = 30.25/.25

= 121

There are twice as many dimes as nickels, so

d = 2n

= 2(121)

= 242

So, there are 121 nickels and 242 dimes. This is easily checked, as 242 dimes makes \$24.20, and 121 nickels makes \$6.05, and that \$24.20 + \$6.05 = \$30.25.