If 8 ml of 0.3 M HCL solution is mixed with 12 ml of distilled water calculate the pH of the diluted solution?

Question

please show your working

Answer 1

pH = -log [H⁺] so we need to find [H⁺]

(8 ml)(0.3 M) = (20 ml)(x M)  the final volume is 20 ml because you added 8 ml to 12 ml

x = 0.12 M HCl

Since HCl is a strong acid, you will have 0.12 M H⁺

pH = -log 0.12 = 0.92