What function represents Midland's population t years after 1990?

Question

The population of Midland, Texas was 89,443 in 1990 and has increases at a rate of 0.6% per year since then. 

Answer 1

0.6% = 0.6/100 = 0.006

Each year the population is 100.6% of what it was

the previous year so it is multiplied by 1.006

 

p(t) = p₀(1.006)^t

 

p(t) represents population after t years

p₀ = starting population = 89,443

t = number of years after 1990

 

p(t) = 89,443(1.006)^t