2 Na(s) + 2 H2O(l) -----> 2 NaOH(aq) + H2(g) ΔHrxn = –368.6 kJ What is the amount of ΔHrxn (in kJ) when 0.5000 moles of Na is reacted completely?

Question

Help please

Answer 1

From the given info, we know the amount of heat released when 2 moles of Na is reacted.  We're asked for the heat per 0.5 moles.  So, (368.6 kJ/2mol)0.5000 mol = 92.15 kJ released.  Therefore, ΔH = - 92.15 kJ