J.R. S. answered 10/19/17
Tutor
5.0
(145)
Ph.D. in Biochemistry--University Professor--Chemistry Tutor
This is an example of Charles Law where pressure is constant.
V1/T1 = V2/T2
Solving for V2:
V2 = V1T2/T1 where T is in Kelvin (ºC + 273)
V2 = (2.0 L)(277K)/275K
V2 = 2.01 L = 2.015 L = 2.0 L (to 2 significant figures)
NOTE: with such a small change in temperature, and with only 2 significant figures used in the original question (2.0 L), the answer of 2.0 L does not show the change in volume.