Prachi G.

asked • 10/18/17

Tough question

x^2+y^2+z^2+1/x^2+1/y^2+1/z^2=6
Find value of x^2+y^2+z^2=?

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Inactive Tutor answered • 10/19/17

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 It seems the only values that make the equation true are x=y=z=(1 or -1), then the answer is 3.
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Inactive Tutor

Prachi from Beverly Hills, CA 90210 (?) sent me a message to explain my answer step by step so here it is.
If x=1 and y=1 and z=1 based on the only possible values that solve the given equation,
then  x^2+y^2+z^2= 1^2 + 1^2 + 1^2 = 1 + 1 + 1 = 3.
MY QUESTION TO PRACHI IS WHERE DO YOU REALLY LIVE?
 
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10/20/17

Prachi G.

 in India.
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10/20/17

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