angular kinematics1

Question

An injured individual has their range of motion assessed during the rehabilitation process.
At full extension the angle between the lower leg and true horizontal is –9°. At full
flexion the angle between the lower leg and true horizontal is 135°. What was the angular
displacement of the knee from full extension to full flexion? Express answer in degrees
and radians

Answer 1

Degrees:

 

135° - (-9°) = 144°

 

Radians:

 

Multiply the degrees by π/180° to get radians.

 

144°(π/180°) = 4π/5 radians