
Andy C. answered 10/16/17
Tutor
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Math/Physics Tutor
One possibility is:
f(x) = C(x-2)(x-2)(x-2)(x-1)(x^2+1) where C is a fixed number constant
f(0) = 8 means that
C(-2)(-2)(-2)(-1)(1) = 8
8C = 8
C = 8/8 = 1
f(x) = (x-2)(x-2)(x-2)(x-1)(x^2+1)