What are the solutions:

Question

x²+x-12

Answer 1

Hi Lynn - does this equation = 0? 

 

If so, then we would have x² + x - 12 = 0

 

This factors into (x + 4)(x - 3) = 0

 

So either (x + 4) = 0 or (x - 3) = 0

 

If (x + 4) = 0, the x = -4

If (x - 3) = 0, then x = 3

 

So the solutions are -4 and 3