Frankie shot an artillery shell at a 40 degree angle. The shell had a muzzle velocity of 230 m/s. How far did the shell go before it hit the ground?

Question

I believe these are the knowns: X- V_xi= 230cos40 (176.19), v_xi = v_xf, ax=0. Y- V_yi= 230sin40 (147.84) v_yf= -147.84, ay= -9.8. I used the equations v_yf=v_yi + at, to find t. I used Δx=v_xit + .5at². I got 5,300 m with sig figs, is this right?

Answer 1

Use the range equation.

 

R = v₀²sin(2θ)/g = (230 m/s)²sin[2(40°)]/(9.8 m/s²) ≅ 5315.95 m