Pre-calc please help

Question

A college decides to build a soccer field and a basketball complex side by side with a fence surrounding the
fields and a shared fence between the two fields. The college has purchased 2300ft of fence for the project

1.  Include appropriate expressions in single variable for each side. Show work for how you got the expressions for the length and width. 

2. What is the maximum area of the two fields together using the 2300ft of fence. 

State your answer clearly list the maximum area and dimensions.

Answer 1

Let x = length of shared side of the fence

     y = length of each side perpendicular to the shared side

 

Then, 3x + 2y  = 2300

 

                  y = (2300 - 3x)/2

 

Area = A = xy = x(2300 - 3x)/2 

 

          A = -(3/2)x² + 1150x

 

Maximum area if x = -1150/[2(-3/2)] = 1150/3 =383 1/3 ft 

 

                        y = 1150 ft

 

 

Answer 2

 

Lot's of questions:

 

   Assuming a rectangular shaped soccer field, how many feet away of the edges of the soccer

   field must the fence be?

 

   Same question regarding the baseball field.

 

   How deep is the outfield of the baseball field, say from second base and behind home plate?

 

   the 2300 feet of fence is for the perimeter, not the area. Why do we need the area?

 

  the fence in the between, does that count as one side shared between the two field or

  is there a double fence in between. I will assume the latter. 

 

  Please repost the problem with more details.

 

 

   Here's the best we can do for now regarding these perimeters.

 

   Baseball field:   4(X+h) where h is a fixed number constant

  

  Soccer field:  2(X+k) + 2(X + C) where k and C are fixed number constants

 

  4(X + h) + 2(X + k) + 2(X +C) = 4x + 2x + 2x + 4h+2k+2C 

 

                                                 = 8x + (4h+2k+2C)

 

So 2300 =  8x + (4h+2k+2C)  

 

     1150 = 4x + (2h + k + c) where h,k, and c are the measures between the playing field and the fence