
Kenneth S. answered 10/02/17
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Expert Help in Algebra/Trig/(Pre)calculus to Guarantee Success in 2018
Does your statement every duck race followed by 5 ducks mean that 5 ducks per heat is a limitation? (That would be better wording).
five heats: a single winner woild NOT be sufficient to determine 5 ducks to participate in a final heat because it COULD happen that the (ultimately) three fastest were in a single first round heat.
Therefore, from each heat of 5 ducks, keep three top finishers.
So the five heats (ea. with 5 ducks participating) would yield 15 possible candidates for the next round of heats.
This second round of heats, 5 ducks per heat, would have 3 heats, and 3 top ducks from each would be selected.
This brings us to 9 candidates; next round has two heats, each heat selecting 3 candidates. (First heat of this round has 5 ducks racing, 2nd heat has 4 other ducks racing).
And from this most recent heat, there are now 6 candidates, so have one heat, 5 racing, and choose the top three finishers. The duck left out is now ready to go to the final heat, in which 4 participate, and thus the top 3 speedsters can be identified.
Review this--if agreed, count up the total number of heats, including the final one having four finalists.
five heats: a single winner woild NOT be sufficient to determine 5 ducks to participate in a final heat because it COULD happen that the (ultimately) three fastest were in a single first round heat.
Therefore, from each heat of 5 ducks, keep three top finishers.
So the five heats (ea. with 5 ducks participating) would yield 15 possible candidates for the next round of heats.
This second round of heats, 5 ducks per heat, would have 3 heats, and 3 top ducks from each would be selected.
This brings us to 9 candidates; next round has two heats, each heat selecting 3 candidates. (First heat of this round has 5 ducks racing, 2nd heat has 4 other ducks racing).
And from this most recent heat, there are now 6 candidates, so have one heat, 5 racing, and choose the top three finishers. The duck left out is now ready to go to the final heat, in which 4 participate, and thus the top 3 speedsters can be identified.
Review this--if agreed, count up the total number of heats, including the final one having four finalists.

Kenneth S.
I think that it's possible that the three fastest ducks might randomly be in the first race. There is no timekeeping so you have to allow for that fact. Fastest in heat 2 might be worse than the abilities of three different (untimed) ducks in the earlier heat.
Re-read my analysis.
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10/02/17
Brian C.
10/02/17