Please can someone answer this

Question

please help

Find the equation of a line with a slope of 3/4 that goes through the point (8, 2).

Answer 1

You may want to use point slope to write the equation of the line, given this information that would be the easiest to use.  The form is Y-Y₁=m(x-x₁)

 

m = slope

x₁ = the x coordinate 

y₁ = the y coordinate

 

therefore, replacing that information into the equation would give you

 

y-2=(3/4)(x-8)

Answer 2

use y = mx + b equation where m is the slope and b is the y-intercept. We are given m which is 3/4. We are also given x and y which are 8 and 2, respectively.

 

so, we plug in these values to solve for b:

 

2 = (3/4)8 + b

 

2 = 6 + b

 

so, b = -4

 

therefore, y = (3/4)x -4

 

 

Answer 3

You want to use the slope-intercept equation for a line. This form is Y =M X + B, or, Y-value = Slope * X-value + Y-Intercept.

 

What we know is an X value, a Y value and a Slope.

X = 8, Y = 2, M = 3/4

 

By substitution we can solve for B

 

2 = 3/4 * 8 + B

 

          or

B = -4

 

Thus equation for the line would be: Y = (3/4) * X - 4

 

The check (should get 2 for Y if plug in 8 for X):

Y = 3/4 * (8) -4 = 6 - 4 = 2