Search
Ask a question
0

Please can someone answer this

please help

Find the equation of a line with a slope of 3/4 that goes through the point (8, 2).

3 Answers by Expert Tutors

Tutors, sign in to answer this question.
Michael M. | Math Tutor MikeMath Tutor Mike
4.9 4.9 (24 lesson ratings) (24)
0
You may want to use point slope to write the equation of the line, given this information that would be the easiest to use.  The form is Y-Y1=m(x-x1)
 
m = slope
x1 = the x coordinate 
y1 = the y coordinate
 
therefore, replacing that information into the equation would give you
 
y-2=(3/4)(x-8)
Ralph L. | Algebra I, II, Visual Basic, Beginning C++ tutorAlgebra I, II, Visual Basic, Beginning C...
4.0 4.0 (1 lesson ratings) (1)
0
use y = mx + b equation where m is the slope and b is the y-intercept. We are given m which is 3/4. We are also given x and y which are 8 and 2, respectively.
 
so, we plug in these values to solve for b:
 
2 = (3/4)8 + b
 
2 = 6 + b
 
so, b = -4
 
therefore, y = (3/4)x -4
 
 
Chris I. | Microbiology Degree and Years of Experience in Computer ScienceMicrobiology Degree and Years of Experie...
5.0 5.0 (1 lesson ratings) (1)
0
You want to use the slope-intercept equation for a line. This form is Y =M X + B, or, Y-value = Slope * X-value + Y-Intercept.
 
What we know is an X value, a Y value and a Slope.
X = 8, Y = 2, M = 3/4
 
By substitution we can solve for B
 
2 = 3/4 * 8 + B
 
          or
B = -4
 
Thus equation for the line would be: Y = (3/4) * X - 4
 
The check (should get 2 for Y if plug in 8 for X):
Y = 3/4 * (8) -4 = 6 - 4 = 2