J.R. S. answered • 09/10/17
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Ph.D. in Biochemistry--University Professor--Chemistry Tutor
To go from 15 mg/L to 1 mg/L represents a 15 fold dilution. So 1/15 th of 50 = 3.3. You would transfer 3.3 ml and dilute to a final volume of 50 ml.
Done another way using C1V1 = C2V2:
(x ml)(15 mg/L) = (50 ml)(1 mg/L)
x = 3.3 ml
J.R. S.
tutor
I'll do a few of them on the already submitted question and hopefully you can do the rest.
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09/11/17
Sonia B.
Standard 3: 100 mL of 0.8 mg/mL ethanol and 2 mg/mL n-propanol in deionised water
Standard 5: 100 mL of 1.5 mg/mL ethanol and 2 mg/mL n-propanol in deionised water
Calculate the required volume of Stock 2 (20 mg/mL of ethanol) that you will need to add to each of five volumetric flasks so that when diluted to 100 mL each will yield the desired ethanol concentrations listed above.
09/11/17