
Arturo O. answered 09/09/17
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The plane needs to get from 0 m/s to 16 m/s at a constant acceleration of 3.2 m/s2. Solve this using the kinematic equation
vf2 - vi2 = 2ad
vf = final speed = 16 m/s
vi = initial speed = 0 m/s
a = constant acceleration = 3.2 m/s2
d = distance over which the acceleration occurs
Solve for d. If d ≤ 50 m, the plane can take off.
d = (vf2 - vi2)/(2a) = (162 - 02)/[2(3.2)] m = 40 m
d = 40 m < 50 m, so there is enough runway for takeoff.