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Sun K.

asked • 04/27/13

Let aT be the tangential component of the acceleration?

Let aT be the tangential component of the acceleration vector of r(t)=<t-sin(t), 1-cos(t), 0>. What is (aT)^2 at t=pi/2?

r'(t)=<1-cos(t), sin(t), 0>

r''(t)=<sin(t), cos(t), 0>

r'(pi/2)=<1, 1, 0>

r''(pi/2)=<1, 0, 0>

Then what should I do?

Sun K.

But the answer is 1/2.

Report

04/28/13

Sun K.

But the answer is 1/2.

Report

04/28/13

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