
Andy C. answered 08/25/17
Tutor
4.9
(27)
Math/Physics Tutor
Ladies first.....
slope M = (4003 - 3833)/(2005 - 2003) = 170/2 = 85
85 students per year.
Since y = Mx + b ---> then b = y - M*x
Using ( 2003, 3833) with M=85, the intercept b is
b = 3833 - 85*2003 = -166422
so the linear model is E (x) = 85*x - 166422
Now for the guys:
(2003, 3097) and (2005, 3321)
The slope M = (3321 - 3097)/(2005 - 2003) = 224/2 = 112
B = y - m*x = 3097 - 112*2003 = -221239
The linear model is E(x) = 112X - 221239
You can check these line equations by plugging in 2005. It works!
Now , it's time to find when the lines will be equal.
112 X - 221239 = 85 X - 166422
112X - 221239 - 85X + 166422 = 0
27X - 54817 = 0
X = 54817/27 = 2030.259259259.... (Sometime in APril 2030)
At that time the population/enrollment will be 6150.