how do you prepare 125ml of 1.5 moles of CaCl2

Question

how do you prepare 125ml of 1.5 moles of CaCl2

Answer 1

Assuming you mean that the 125 ml of solution should contain 1.5 moles of CaCl2, then you would do the following:

Determine how many grams are in 1.5 moles of CaCl2

• molar mass CaCl2 = 110.98 g/mole

 

Determine how many grams are in 1.5 moles CaCl2

• 110.98 g/mole x 1. 5 moles = 166.47 g

Dissolve this mass in sufficient volume to make a final volume of 125 ml

 

If you mean to make 125 ml (0.125 L) of a 1.5 molar (M) CaCl2 solution, that is quite different.

1.5 mol/L x 0.125 L = 0.1875 moles CaCl2 needed

0.1875 moles x 110.98 g/mole = 20.8 g

Dissolve 20.8 g CaCl2 in sufficient solvent (water) to make a final volume of 125 ml.