
Andy C. answered 07/22/17
Tutor
4.9
(27)
Math/Physics Tutor
Let X represent the number of students that have BOTH ear and nose piercing.
7 have nose and possibly ear pierced, so 7-X of them have only nose pierced.
Likewise, 26 have ears and possibly nose pierced, so 26-x of them have only ears pierced.
There are 30 altogether.
So # with only nose pierced + # with BOTH nose and ears pierced + # with only ears pierced = 30
7-X + X + 26-X = 30
33 - x = 30 <--- combining like terms
33 - x - 30 = 0 <--- solving for X
3 - x = 0
3 = x
x = 3
4 students have only nose pierced
23 student have only ears pierced
3 have both nose and ears pierced
the total is 30.
Final answer is 3