Araceli G.
asked • 07/06/17
S=2piR^2+2pi Rh solve for h
Arturo O.
answered • 07/06/17
Experienced Physics Teacher for Physics Tutoring
Given: S = 2πR2 + 2πRh
Solve for h.
S - 2πR2 = 2πRh
(S - 2πR2) / (2πR) = h
h = (S - 2πR2) / (2πR) = S/(2πR) - R
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