Sava D. answered 06/26/17
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We need to find how many number we are adding.
an=a1+(n-1)q
an=184, a1=13.
The common difference q = 22 -13 = 9.
We replace these values in the equation (1) and find n.
184 = 13 +(n-1)9
184 - 13 = 9n - 9
171 = 9n-9
180 = 9n,
n = 20.
Here is the summation notation:
ak=13+(k-1)9
Σ20k=1(ak) =13 +22 + 31+ ... +184.