Here f'(x) is -1/x^2. Plugging in c that's -1/c^2 equal to (1/9-1/3)/6 or -2/9/6=-1/27. So c is square root of 27.
Dalia S.
asked 06/15/14Find the average or mean slope of the function on this interval.
Consider the function f(x)=1/x on the interval [3,9]. Find the average or mean slope of the function on this interval.
By the mean value theorem, we know there exists a c in the open interval (3,9) such that f'(c) is equal to this mean slope. For this problem, there is only one c that works. What is it?
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