PIYUSH L. answered • 06/04/14

Tutor

5
(6)
Maths tutoring for middle school to college maths students

It is given that f(2) = 6 grams

The rate of change of weight at time t= 2 will be

fprime(2) =-5*f(2)*(5+f(2)) = -5*6*(5+6) = -330 gms / minute = -0.727 pounds / minute = -0.012 pounds / sec

Therefore the weight of the ice at time = 2 is decreasing by 0.012 pounds / sec

Its weight after 1 second will be 6 - 0.012 = 5.988 pounds

PIYUSH L.

I apologize for the error. Please note the correction.

As shown above,

fprime(2) =-5*f(2)*(5+f(2)) = -5*6*(5+6) = -330 gms / minute

-330gms / minute = -330 gms / 60 sec = 5.5 gms / sec

Therefore the weight of the ice at time = 2 is decreasing by 5.5 gms / sec

Its weight after 1 second will be 6 - 5.5 = 0.5 gms

Its weight after 1 second will be 6 - 5.5 = 0.5 gms

Report

06/05/14

Dalia S.

06/04/14