Dalia S.

asked • 06/04/14

Estimate the amount of solid 1 second later

Let f(t) be the weight (in grams) of a solid sitting in a beaker of water after t minutes have elapsed. Suppose that the solid dissolves in such a way that the rate of change (in grams/minute) of the weight of the solid at any time t can be determined from the weight using the forumula:
 
fprime(t)=-5f(t)(5+f(t))
 
If there is 6 grams of solid at time t=2 estimate the amount of solid 1 second later.

1 Expert Answer

By:

PIYUSH L. answered • 06/04/14

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Dalia S.

the answer is incorrect
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06/04/14

PIYUSH L.

I apologize for the error. Please note the correction.
 
As shown above,
 
fprime(2) =-5*f(2)*(5+f(2)) = -5*6*(5+6) = -330 gms / minute
 
-330gms / minute = -330 gms / 60 sec = 5.5 gms / sec
 
Therefore the weight of the ice at time = 2 is decreasing by 5.5 gms / sec

Its weight after 1 second will be 6 - 5.5 = 0.5 gms
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06/05/14

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