Inactive Tutor answered • 06/02/14
Tutor
New to Wyzant
f(X) = (ln(7-X2))(1/3)
f'(X) = (1/3)* (ln(7-X2))(-2/3) * (1/(7-X2)) * (-2X)
for X=1 we have:
f'(X) = 0.2259
Inactive Tutor
Please post your answer and the solution to compare, I can not be trying to give a number that i do not know.
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06/03/14
Dalia S.
we are not provided with the solutions, they simply tell us whether the answer is correct or incorrect and in this case it was incorrect. I tried solving it on my own and for f prime x i got 2x/3(x2-7)log2/3(7-x2). How would i go
about solving for x=1? do i just plug in 1 where ever there is an x?
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06/03/14
Inactive Tutor
yes that is the way of doing it
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06/03/14
Dalia S.
06/03/14