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Question

If 150g of carbon react with 250g of cl₂ and the reaction has an 85% yield , how many gram of ccl₄ are produced ?

Answer 1

The reaction will be C + 2Cl₂ ----> CCl₄  (balanced equation)

 

molar mass of C is 12g/mol, molar mass of Cl₂ is 70.9g/mol and molar mass of CCl₄ is 154g/mol

 

1. We need to calculate the number of moles of carbon: 150g of C divided by 12g/mol = 12.5 mol C

2. We need to calculate the number of moles of Cl₂: 250g of Cl₂ divided by 70.9g/mol = 3.53 molCl₂

3. We can see from the number of moles of each species that C is in excess, therefore Cl₂ is the limiting reactant.

4. For 2 moles of Cl₂, you generate 1 mole of CCl₄; therefore, for 3.53 mol of Cl₂, you will generate 1.77 mol of CCl₄ (3.53 mol/2).

5. The expected number of moles of CCl₄ is 1.77; therefore you expect to generate 1.77mol x 154g/mol = 272g of CCl₄ (if you get 100% yield).

6. Yield being 85%, you will multiply 272g of CCl₄ by 0.85 (85%) and you will get 231g of CCl₄

 

Hopefully the answer is clear enough.