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The disk of a sander has a radius of 6 inches and is rotating at a speed of 5 revolutions per second.

a. Find the angular speed of the sander disk in radians per second. 
b. What is the linear velocity of a point on the edge of the sander disk in feet per second?
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1 Answer

a. one revolution =2pi radians so 5 rps= 10*pi rad/sec
b.v=r*ω where r=radius in ft and ω= angular speed in rad/sec
so v=.5*31.42=15.71 ft.sec