*Three times a number minus two times another number equals 19. The sum of the two number is 18. find the two numbers*

*hree times a number minus two times another number equals 19*

*The sum of the two numbers is 18*

three times a number minus two times another number equals 19. The sum of the two number is 18. find the two numbers

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Let m = one of the numbers and n = the other number

We have two unknowns (n and m), so we need two equations relating them to find the solution.

Equation 1 - T*hree times a number minus two times another number equals 19*

3m - 2n = 19

Equation 2 - *The sum of the two numbers is 18*

m + n = 18

We can re-write this equation as:

n = 18 - m

Now let's substitute 18-m in place of n in Equation 1:

3m - 2n = 19 (equation 1)

3m - 2(18-m) = 19 (Substitute 18-m in place of n)

3m - 36 +2m = 19 (Multiply out the parentheses)

5m = 55 (Add the m terms, add 36 to both sides)

Solve for m, then use n = 18 - m to solve for n. Check your answers by putting them into equation 1 and verifying that they produce 19 for the answer.

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