How many grams of water (H2O) will be produced when 15.98g of hydrochloric acid (HCl) is neutralized by an excess of NaOH

Question

How many grams of water (H2O) will be produced when 15.98g of hydrochloric acid (HCl) is neutralized by an excess of NaOH

 

Answer 1

First, write the balanced equation for the reaction:

HCl + NaOH ===> NaCl + H2O  Balanced Equation

 

Since there is excess NaOH, moles of water will be equal to moles of HCl present.

moles HCl = 15.98 g HCl x 1 mole HCl/36.5 g = 0.438 moles HCl

moles H2O produced = 0.438 moles HCl x 1 mole H2O/mole HCl = 0.438 moles H2O produced

mass H2O produced = 0.438 moles H2O x 18 g H2O/mole H2O = 7.884 grams H2O produced (to 4 sig.figs)