
Katherine C. answered 05/25/17
Tutor
4.8
(53)
Effective Chemistry Tutor: Organic, Gen Chem, AP Chem + Graduate level
I agree with the previous answer, but if you need it stated with rate laws:
All radioactive decay is first order.
The half life is related to the rate constant for a first order reaction by the equation t1/2 = ln2
k
Substituting in the half life for C14, 5730 yrs = ln 2 k = 1.2097 x 10-4 yr-1
k
The first order rate equation is ln [At] = -k t If 99.8% has been lost, the remainder [At] is 0.002 and [At]/[A0] =
[A0] 0.002/1 = 0.002
ln 0.002 = -1.2097 x 10-4 t
t = ln 0.002 = 51373 yrs This should probably be reported as ~50,000 years or ~51,000 yrs based on
-1.2097E-4 the significant figure rules for logarithms.