A drama club earns $1040 from a production. It sells a total of 64 adult tickets and 132 student tickets. How much is each ticket?

Question

Can someone please help me with this problem and show me the steps how to do it? 

Answer 1

i think i found the rest of the question

 

"A drama club earns $1040 from a production. A total of 64 adult tickets and and 132 student tickets are sold. An adult ticket costs twice as much as a student ticket. what is the cost of each ticket?"

 

if this is the right problem statement, then the answer is 8 and 4

Answer 2

Let a = price of adult ticket

Let s = price of student ticket

 

64a + 132s = 1040

 

We have one equation with 2 unknowns.  We need more

information to solve the system.

Answer 3

let x = price of adult tickets, and let y = price of student tickets

 

then:  64x + 132y = 1040; or, dividing each side of the equation by 4  

--->  16x + 33y = 260;  this is the equation of a straight line in the

 

        x-y plane;  there are an infinite number of points on this straight

 

        line, each of which (theoretically) is a possible solution, except

 

        that x and y are (presumably) in dollars and cents, which means

 

        that x and y are each of the form dd.dd; that is to say, that the

 

       decimal portion of each of x and y contains at most two non-zero

 

       digits; that should rule out at least some of the infinite number of

 

       solutions;  that should still leave "many" solutions;  for example,

 

      if y = 4.00, then:  16x + 4(33) = 260; 16x + 132 = 260;

 

      16x = 260 - 132 = 128; x = 128/16 = 8.00;  this could be one

 

      possible solution;  but, there must surely be others;  

 

      so, let's try x = 2.00;  then, 16x + 2(33) = 260;

 

     or, 16x + 66 = 260; or, 16x = 260 - 66 = 194;  or, x = 194/16

 

     or, x = 160/16 + 34/16 = 10 + 32/16 + 2/16 = 12 + 1/8 =

 

    12.125, so that didn't quite work

 

    so, try x = 3.00; then:  16(3) + 33y = 260;  33y + 48 =  260;

 

    then, 33y = 260 - 48 = 212;  or y = 212/33; or, y = that's not

 

   going to work either;  don't tell me I stumbled onto the correct

 

   answer, namely x =$4.00; y = $8.00;  there must be other

 

   solutions(I would think)  --- that's enough for now --- further

 

   investigation is needed, though