sinθ=2/5. cos2θ=1-sin2θ gives cos2θ=1-4/25=21/25
cosθ<0 gives cosθ=-(√21)/5
sin2θ=2sinθcosθ=2×(2/5)×(-(√21)/5)=-4(√21)/25
cos2θ=cos2θ-sin2θ=21/25-4/25=17/25
Jackie S.
asked 05/18/17
Kenneth S. answered 05/18/17
Expert Help in Algebra/Trig/(Pre)calculus to Guarantee Success in 2018
Get a free answer to a quick problem.
Most questions answered within 4 hours.
Choose an expert and meet online. No packages or subscriptions, pay only for the time you need.