
Kris V. answered 05/17/17
Tutor
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Experienced Mathematics, Physics, and Chemistry Tutor
Any real number can be expressed as the sum of its integer part and its fractional part, i.e.
x = [x]+{x}
Substituting {x} = x - [x] into [x]2 = x + 2{x} yields
[x]2 = 3x - 2[x]
[x]2 +2[x] = 3x
[x]2 +2[x] +1 = 3x +1. Adding 1 to both sides to complete the square of the left hand side (LHS)
[x] = SQRT(3x +1) - 1
Since SQRT(3x +1)≥ 0 and [x] must be an integer, the solution x can be found by
letting 3x +1 equal to 0, 1, 4 or 9 and solve for x.
The solutions are -1/3, 0, 1 and 8/3.