"perpendicular" means forming a 90 degree (or right angle) angle with. So (1) equation of the line that is: perpendicular to the line y=4x+1 and that passes through the point (2,3) can be solved by finding the slope of the perpendicular line first. The slope of a line perpendicular to another line is basically the negative reciprocal....So the slope of line will be -(1/4). so now we have a portion of our equation....y= -(1/4)x+b.....Now we need to find the value of b. We plug in the point (2,3) in for (x,y) to get
3= -(1/4)*2 + b
Solving for b yields 3 + (1/4)*2 = 3.5
So for # 1....our equation of the line perpendicular is y= -(1/4)x + 3.5
For # 2, do the same, but the parallel line will have the same slope.
For # 3, first solve for y, then find the slope of the line perpendicular, etc.....
For # 4, "parallel to the line y=4x+3 and that has the same y-intercept as the line y=5x-3" . The y intercept of y=5x-3 is -3. So since the parallel line has the same slope as 4x, then our parallel line is y=4x-3.
Hope this helps....I can't do every single one for you....you wouldn't learn anything.