find the pressure of a gas at 203.6 kpa, 40 liters and 75 degree celsius, if transfered to a 20 liter tank at -10 degree celsius

Question

                                                          dd

Answer 1

So p1*v1/t1 = p2*v2/t2.......p=pressure, v=volume, and t= temperature in kelvin. So your kelvin temperatures are

75 C = 348.15 K and -10 C = 263.15 K

 

So 203.6*40/348.15 = p*20/263.15

2143093.6               = 6963 p

307.783082             =  p

 

Hope this helped.