
Herb K. answered 05/07/17
Tutor
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Semi-Retired College Professor - MIT Grad - very patient, experienced
let x = number of horses in first stable now ---> x = y + 20 now ---> later, there will be x + 8 = y + 28 horses in stable 1
let y = number of horses in second stable now ---> later, there will be y + 2 horses in stable 2
thus, y + 28 = 3(y + 2) ---> y + 28 = 3y + 6 ---> 2y = 22 ---> y = 11; and x = y + 20 = 11 + 20 = 31