ok, its been a long time since i've done algebra (20 years). Here is the problem:

Woman sells dog leashes and collars on the weekends at dog shows. One weekend she sold a total of 34 leashes. The number of leashes she sold was two less than three times the number of collars. How many of each did she sell?

This is how I solved it=

3 ( X - 2 ) = 34

3X - 6 = 34

3x = 40

40 / 3

X= 13

Leashes are 13- 2 = 11

Collars = 3 (11)

But that gets me 44 (when I add the two numbers back and not the 34). Where am I going wrong?

Thanx

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34=3x-2

"Thirty four leashes (34) equals (=) two less than (-2) three times the number of collars (3x)"

Add two to both sides:

36=3x

Divide both sides by 3:

12=x

Check:

34=3(12)-2

34=36-2

34=34

Please contact me if you have any questions. Thanks!

let C=# of collars

34=3C-2

36=3C

12=C, the number of collars

34 is 2 less than 3x12 which equals 36

If you meant to say that 34 is the total number of leashes *and *collars sold, then we do the problem differently.

L+C=34

L+2=3C

L=3C-2

substitute 3C-2 for L in the first equation

3C-2+C=34

4C-2=34

4C=36

C=9 collars

34-9=25 leashes

25 is 2 less than 3x9=27

I sm sorry I am still not seeing it. The number of leashes sold should be 2 less than 3 times the number of collars. Both numbers have to equal 34.

so is the equation 34 (total leashes) = 3 x + x - 2

34 = 4 x - 2

34 + 2 =

34 = 4 x

Divide by 4 which gives 9

9 = x

Multiple 3 times 9 gives you 27 then subtract 2 which gives me 25

So 25 leashes

9 collars

????

i meant 36 = 4 x which gives me 9 = x

Adam S. | Professional and Proficient Math TutorProfessional and Proficient Math Tutor

Q: Woman sells dog leashes and collars on the weekends at dog shows. One weekend she sold a total of 34 leashes. The number of leashes she sold was two less than three times the number of collars. How many of each did she sell?

A: The problems states that she sold a total of 34 leashes. It also says that the number of leashes sold was two less than three times the number of collars.

Let L = number of leashes and C = number of collars.

L is stated in the problem. L = 34.

L = 3C - 2.

Solving for C -> C = 1/3*(L + 2).

L = 34.

C = 1/3*(L + 2).

I think you misunderstood the problem. The number of leashes is already stated in the problem. The trick is to find the number of collars by forming an equation from the information given in the question.

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## Comments

So I need to find the number of leashes and number of collars.