
Sophie M. answered 04/13/17
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Experienced Tutor with Stanford B.S. in Engineering Physics
Let's set this up as a system of equations:
x*v1 + y*v2 = (11 4 m) can be expanded to:
Eq 1: x + 2y = 11
Eq 2: 2x + 3y = 4
Eq 3: 5x + 2y = m
Since m only appears in Eq 3, we can solve equations 1 and 2 independently.
2*Eq 1: 2x + 4y = 22
-1* Eq 2: -2x - 3y = -4
-1* Eq 2: -2x - 3y = -4
y = 18 (by summing the equations)
x + 2(18) = 11 (plugging y value back into Eq 1)
x = -25
Now let's plug x = -27, y = 18 back into Eq 3:
5(-25) + 2(18) = m
m= -89