
Steve S. answered 03/22/14
Tutoring in Precalculus, Trig, and Differential Calculus
f(x) = 3/((x+2)(x-2)) – 7(x-2)/((x-2)(x+2))
f(x) = (3 – 7(x-2))/((x-2)(x+2)), x ≠ ±2
f(x) = (17–7x)/((x-2)(x+2)), x ≠ ±2
Partial Fractions simplify further for use in calculus:
f(x) = (17–7x)/((x-2)(x+2)) = A/(x-2) + B/(x+2)
17–7x = A(x+2) + B(x–2) = (2A-2B) + (A+B)x
A + B = -7
2A-2B = 17
2A+2B =-14
4A = 3
A = 3/4
B = -A - 7 = -3/4 -28/4 = -31/4
f(x) = 3/(4(x-2)) – 31/(4(x+2)), x ≠ ±2
Steve S.
03/21/14