The volume of a gas is 25.6 mL at 32◦C and 0.891 atm. What will the volume be at 16◦C and 1 atm?

Question

Ive tried every equation an I still cant get the answer 

Answer 1

Assuming it is an ideal gas, use the relation

 

P₁V₁/T₁ = P₂V₂/T₂

 

V₂ = P₁V₁T₂ / (T₁P₂)

 

Use absolute temperatures only:

 

T₁ = (32 + 273)K = 305 K

T₂ = (16 + 273)K = 289 K

 

V₂ =  (0.891 atm)(25.6 mL)(289 K) / [(305 K)(1 atm)] = 21.61 mL