Word Problem

Question

The length of a rectangular ballroom is 7 feet longer than twice the width. If the room's perimeter is 182 feet, what are the ballrooms dimensions?

Answer 1

L = 7+2w

182 = 2L +2w

91 = L + w = 7+2w+w = 7+3w

3w = 91-7 = 84

w = 84/3 = 28 feet wide

L = 7+2(28) = 63 feet Long

182 = 2x63 +2x28 = 126+56 = 182 feet Perimeter

Answer 2

Hi Marvin,

 

let the width be w, the length l and the perimeter P.

Then l = 2w + 7

P = 2*(w+(2w+7))

182 = 6w + 14

Can you solve for w? It should be 28. Then, you can find l, too. Let me know if you have nay problems moving forward.