Consider the graph of the following quadratic equation. Y= -x^2-10x + 24 What is the y-value of the vertex?

Question

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Answer 1

Did you mean "y = x^2 - 10x + 24"?

Ok, so calculating the vertex involves setting x = -b / 2a where a = 1, b = -10 and c = 24. x = 10 / 2 = 5 Plug x = 5 into the equation to find y. You get y = -1 (your answer). So, the vertex is (5,-1).