
Valmiki R. answered 04/08/17
Tutor
4.9
(44)
Master's in Chemical Engineering
Two equations you need to know are:
dG = R T ln(Kp)
dG= dH-TdS
At standard conditions (25C, 1 atm), we are told dG= 65.1 kJ/mol
dG = R T ln(Kp)
65100=(8.314)(273+25)(ln(Kp))
∴Kp =2.58x1011 atm7
NB: this Kp looks very large.