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Vertical shifts

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2 Answers

There are a few different ideas you need to know here.
When graphing, y = f(x)...
Stretch / Compression
Replacing x with (ax) is a horizontal stretch/compression. y = f(ax)
Multiplying to get y = a*f(x) is a vertical stretch/compression.
You should also remember
For vertical moves, if a>1, the graph is stretching out vertically.
For horizontal moves, if a>1, the graph is compressing in horizontally. 
Replacing x with (x-b) is a horizontal shift. Moves entire graph left or right
y = f(x) + b is a vertical shift. Moves entire graph up or down
In this case function y= f(x) is y=logx.

logx(a*b) = logx(a)+logx(b)
When a base x is not shown, it is commonly assumed base x is 10.
log10(10a) = a
OK so knowing all this, now we can start the problem... Wow.
y = logx      AND     y = log10x
y = log(10x), we are replacing x with 10x. x>1 Therefore, this is a horizontal compression.
y = log10x = log10 + logx
y = 1+logx
y = logx + 1   Therefore, this is vertical shift of y = logx. The graph moves up 1.
I know this is a lot of information, but if you take the time to understand all these ideas, you will likely be ahead of your class!
graph y=logx, y=log(10x), and y=log(100x). how do the graphs compare? use a property of logs to show that the graphs are vertical shifts of one another.

Eric's explanation is confusing because of the typos in it.

So let me try:

f(x) = log(x)

g(x) = log(10x) = log(10^1) + log(x) = log(x) + 1 = f(x) + 1

h(x) = log(100x) = log(10^2) + log(x) = log(x) + 2 = f(x) + 2

So g is f shifted up 1 and h is f shifted up 2.

Eric also explained dilation ("Honey, I shrunk the kids!"), but that's not needed for this problem.

Here’s a GeoGebra graph of the three functions: