Is 3e(2e+3) divisible by 7????

Question

Is 3e(2e+3) divisible by 7?

 

i know its simple but im horrible at math

Answer 1

If e is just a variable, then 3e(2e+3) is divisible by 7 when either factor is divisible by 7.

3e is divisible by 7 if e = 7n/3, n a multiple of 3.

2e+3 is divisible by 7 if:
  2e+3 = 7n
  e = (7n - 3)/2 = (4n+3n-3)/2 = 2n+(3/2)(n-1)
  if n is odd, then n-1 is even and divisible by 2, so
  2e+3 is divisible by 7 if e = (7n - 3)/2, n odd.

If e is the irrational Euler number, 2.718281828459045…, then both factors are irrational and not divisible by 7; i.e., the remainder will not be 0.

Answer 2

2*10³ = 2000

 

3e(2e+3) = 3x10²⁰⁰⁰ =3 x 2²⁰⁰⁰ x 5²⁰⁰⁰

 

This is a prime factorization of the number given.

For a number to be divisible by 7. There must be a 7 in the prime factorization of the number.

Answer: no