The sum of three consecutive integers is 24 larger than twice the smallest integer. Find the integers. (Enter your answers as a comma-separated list.)

Question

STUCK ON MATH.

Answer 1

Hey Versace, you would need to set up an algebraic equation to represent what it says.

 

Let us set the first of the three integers as n. Therefore, the number after would be n+1 and the next would be n+2.

 

24 = n+(n+1)+ (n+2) 

24 = 3n+3

n = 7

Thus, the three consecutive numbers would be 7,8,9.