
Steve S. answered 03/16/14
Tutor
5
(3)
Tutoring in Precalculus, Trig, and Differential Calculus
A(t) = B(1/2)^(kt)
A(0) = B(1/2)^(k*0) = B
A(t) = A(0)(1/2)^(kt)
1/2 = 1(1/2)^(15k)
15k = 1
k = 1/15
A(t) = A(0)(1/2)^(t/15)
A(105) = 256(1/2)^(105/15)
A(105) = (2^8)(1/2)^(7)
A(105) = (2^8)/(2^7) = 2 mg